题目描述

模板题：高精度除法

C++代码

#include <bits/stdc++.h>
#include <vector>
using namespace std;

vector<int> div(vector<int> &A, int b, int &r){
    vector<int> C;
    r = 0;
    for(int i = A.size() - 1; i >= 0; i--){
        r = r * 10 + A[i];
        C.push_back(r / b);
        r %= b;
    }
    reverse(C.begin(), C.end()); //由于除法从高位开始算，所以要reverse
    while(C.size() > 1 && C.back() == 0) //可能存在商前面几位全是0情况
        C.pop_back();
    return C;
}

int main(){
    string a;
    int b;
    vector<int> A, C;
    cin >> a >> b;
    for(int i = a.size() - 1; i >= 0; i--)
        A.push_back(a[i] - '0');
    int r;
    C = div(A, b, r);
    for(int i = C.size() - 1; i >= 0; i--)
        cout << C[i];
    cout << endl;
    cout << r << endl;
}